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Java Stream program to find all even numbers from a list

Approach 1

import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class EvenNumberStreamExample {
    public static void main(String[] args) {
        // Sample list of integers
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);

        // Use Stream API to filter even numbers
        List<Integer> evenNumbers = numbers.stream()
                                           .filter(n -> n % 2 == 0)
                                           .collect(Collectors.toList());

        // Print the even numbers
        System.out.println("Even numbers: " + evenNumbers);
    }
}

Approach 2 Using Collectors.partitioningBy() – To classify into even and odd

import java.util.*;
import java.util.stream.Collectors;

public class EvenNumbersUsingPartitioning {
    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6);

        Map<Boolean, List<Integer>> partitioned = numbers.stream()
                                                         .collect(Collectors.partitioningBy(n -> n % 2 == 0));

        List<Integer> evenNumbers = partitioned.get(true);

        System.out.println("Even numbers: " + evenNumbers);
    }
}

Approach 3

import java.util.*;
import java.util.stream.*;

public class Main {
    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(1, 2, 3, 4, 5, 6);

        List<Integer> evens = list.stream()
            .collect(Collectors.filtering(n -> n % 2 == 0, Collectors.toList()));

        System.out.println(evens);
    }
}